# Force Exerted on Hinged Plate

## Force exerted on the jet toward a hinged plate

- Think of a jet of water striking a vertical plate in the middle which is hinged plate at O.
- Due to the force exercised by the jet toward the plate, that plate will swing through some angle on the hinge.

Let,

x = distance of the centre of a jet from hinge O,

θ = angle of swing about a hinge,

W = weight of plate acting at C.G. of the plate.

- The dotted lines show the position of the plate before the jet strikes the plate.
- Point A on the plate will be at A’ after the jet strikes the plate.
- The distance
**OA = OA’ = x**. - Let the weight of the plate is acting at A’.
- If the plate is in equilibrium after the jet strikes the plate, the moment of all the forces about the hinge must be zero.
- Two forces are acting on the plate. They are….!

Force due to a jet of water, normal to the plane,

Fn = ρav^2 sinθ1

where,

θ1 = Angle between jet and plate

**= (90o – θ) **

Weight of plate, W

Moment of force Fn about hinge

= Fn x OB

= ρav^2 sin(90o – θ) x OB

= ρav^2 cosθ x OB

= pav^2 cosθ x (OA/cosθ)

= ρav^2 x OA

**= ρav^2 x x**

Moment of weight W about hinge

= W x O A’ sinθ

= W x x x sinθ

For equilibrium of the plate,

ρav^2 x x = W x x x sinθ

**sinθ = (pav^2/W)**